100 팩토리얼을 계산한후, 각 자리수를 더하는 문제입니다.
Factorial digit sum
n! means n × (n − 1) × ... × 3 × 2 × 1
For example, 10! = 10 × 9 × ... × 3 × 2 × 1 = 3628800,
and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.
Find the sum of the digits in the number 100!
팩토리얼 계산
1 2 3 4 5 6 7 8 | def fact(num): total=1 while num>0: total*=num num-=1 return total fact(10) |
3628800
1 2 3 4 5 6 7 | def fact(num): total=1 for i in range(1,num+1): total*=i return total fact(10) |
3628800
1 2 3 4 5 6 | def fact(num): if num==1: return 1 return num*fact(num-1) fact(10) |
3628800
1 2 | from math import factorialfactorial(10) |
3628800
자릿수 합
1 2 3 4 5 6 7 8 9 10 11 12 13 | def fact(num): total=1 for i in range(1,num+1): total*=i return total result=fact(10)string=str(result)total=0for i in string: total+=int(i)print(total) |
27
100 팩토리얼 계산
1 2 3 4 5 6 7 8 9 10 11 12 13 14 | def fact(num): total=1 for i in range(1,num+1): total*=i return total result=fact(100)print(result)string=str(result)total=0for i in string: total+=int(i)print(total) |
93326215443944152681699238856266700490715968264381621468592963895217599993229915608941463976156518286253697920827223758251185210916864000000000000000000000000 648
